Reference - Scandic hotel Oulu City
Hotels seek energy efficiency by reducing water consumption. The Scandic hotel in Oulu ended up choosing the showers with the best washing power and did not compromise on the comfort of the customers.
When comparing the years 2022 and 2024, a big change was seen in water consumption:
- 27 liters / overnight stay / room
- The hotel's total water consumption dropped by 19%
How do I calculate hotel savings?
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How much money did the hotel save in euros?
1. Determine the price of district heating in Oulu:
The price of district heating can vary, but according to the latest information, district heating in Oulu costs around 70-80 EUR per MWh (megawatt hour). An average price of 75 EUR per MWh is used here.
2. Convert the saved energy into megawatt hours:
Previously, it was calculated that the energy saved is 313.5 kWh per day. Let's convert this to megawatt hours:
Adjusted energy (MWh)=1000313.5 kWh≈0.3135 MWh
3. Calculate the savings in euros:
Now the saved energy is multiplied by the price of district heating:
Daily savings (EUR)=0.3135 MWh×75 EUR/MWh≈23.51 EUR
4. Annual savings:
Annual savings assuming the hotel operates 365 days a year:
Annual savings = €23.51/day × 365 days ≈ €8579.15/year
Summary:
- Daily savings: About 23.51 EUR per day.
- Annual savings: About EUR 8,579.15 per year.
By reducing hot water consumption, the Reference Hotel in Oulu saves about 23.51 EUR per day, which is about 8,579.15 EUR per year, assuming that the savings are constant throughout the year.
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Reduction of CO2 emissions
Let's calculate the CO2 emissions saved by the Reference hotel based on the reduction of hot and cold water consumption.
The emission factor of district heating is usually lower than that of electricity, and it varies by region. In Oulu, the emission factor of district heating is about 0.110 kg CO2 per kWh . Let's use this value in the calculation.
1. Information given:
- Number of rooms: 200
- Daily water consumption reduction: 27 liters / room
- Daily total water saving: 5400 liters (27 liters / room * 200 rooms)
2. Energy needed to heat water:
We assume that the water needs to be heated from a cold temperature (e.g. 10°C) to a typical warm water temperature (e.g. 60°C).
- Temperature rise: 50°C (10°C60°C)
- Energy requirement per liter per degree: 4.18 kJ
Calculate the energy saved:
Energy saved (kJ) = 5400 × 50 x 4.18 = 1,128,600 KJ
Hotel values are used
Energy saved (kJ)= 5400 × 50 × 4.18 = 1,128,600 kJ
Convert the saved energy into kilowatt hours (kWh):
Energy saved (kWh) = 1128600 kJ / 3600 ≈ 313.5 kWh
3. Reduction of CO2 emissions:
It is assumed that the emission factor of district heating is 0.110 kg CO2 per kWh.
Reduction of CO2 emissions (kg) = 313.5 kWh × 0.110 kg CO2 / kWh ≈ 34.49 kg CO2
4. Calculation summary:
- Total water saving: 5400 liters per day
- Energy saved: 313.5 kWh per day
- Reduction of CO2 emissions: 34.49 kg CO2 per day
This calculation shows that by reducing water consumption by 5,400 liters per day, the Reference Hotel saves approximately 34.49 kg of CO2 emissions every day when district heating is used to heat water in Oulu. This is a significant improvement that contributes to both energy savings and reducing the hotel's carbon footprint.
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